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Section 14

Refinement by the exceptional plane of a point blow-up

Fix p∈Xp\in X, and write σ:Y=BlpX→X\sigma:Y=\mathop{\mathrm{Bl}}_pX\to X and G=σ−1(p)G=\sigma^{-1}(p). Then G≅ℙ(TpX)≅ℙ2G\cong\mathbb P(T_pX)\cong\mathbb P^2, G|G=𝒪ℙ2(−1)G|_G=\mathcal O_{\mathbb P^2}(-1) and KY=σ*KX+2GK_Y=\sigma^*K_X+2G. In particular, AX(G)=3A_X(G)=3. We reserve EE for the exceptional divisor of X→ℙ3X\to\mathbb P^3.

Put Rm=H0(X,mL)R_m=H^0(X,mL) and Nm=dimRmN_m=\dim R_m. After trivializing LL near pp, define ℱjRm=H0(X,mL⊗𝔪pj),Wm,j=ℱjRm/ℱj+1Rm⊂H0(G,𝒪G(j)).\mathcal F^jR_m=H^0(X,mL\otimes\mathfrak m_p^j),\qquad W_{m,j}=\mathcal F^jR_m/\mathcal F^{j+1}R_m \ \subset\ H^0(G,\mathcal O_G(j)). The inclusion sends a section to its homogeneous leading term of degree jj at pp. Equivalently, Wm,jW_{m,j} is the image of restriction from H0(Y,mσ*L−jG)H^0(Y,m\sigma^*L-jG) to GG. In particular, it is the image of restriction, not a complete linear system by definition. We have ∑jdimWm,j=Nm\sum_j\dim W_{m,j}=N_m.

For a prime divisor QQ over GG, let Sm(W;Q)S_m(W;Q) be the largest value of 1mNm∑j∑i=1dimWm,jordQ(sj,i),\frac1{mN_m}\sum_j\sum_{i=1}^{\dim W_{m,j}}\mathop{\mathrm{ord}}_Q(s_{j,i}), where {sj,i}i\{s_{j,i}\}_i is a basis of Wm,jW_{m,j}, and where orders mean orders of the corresponding zero divisors on GG. Write S(W;Q)S(W;Q) for its asymptotic limit and define δ(G;W)=infQAG(Q)S(W;Q).\delta(G;W)=\inf_Q\frac{A_G(Q)}{S(W;Q)}. This is the stability threshold of a multigraded series on ℙ2\mathbb P^2; it is not automatically the threshold of a complete linear system on ℙ2\mathbb P^2.

Lemma 14.1 (Abban–Zhuang at a point). For every p∈Xp\in X, (14.1)δp(X)≥min{3SX(G),δ(G;W)},SX(G)=116∫0∞vol(σ*L−tG)dt.\label{f29:eq:point-AZ} \delta_p(X)\ge \min\left\{\frac3{S_X(G)},\ \delta(G;W)\right\},\qquad S_X(G)=\frac1{16}\int_0^\infty\mathop{\mathrm{vol}}(\sigma^*L-tG)\,dt. Moreover, putting λ=min{3/SX(G),δ(G;W)}\lambda=\min\{3/S_X(G),\delta(G;W)\}, every divisorial valuation vv centred at pp satisfies (14.2)AX(v)≥λSX(v)+(3−λSX(G))v(𝔪p).\label{f29:eq:point-strong} A_X(v)\ge\lambda S_X(v)+(3-\lambda S_X(G))v(\mathfrak m_p). Consequently, if SX(G)<3S_X(G)<3 and δ(G;W)≥1\delta(G;W)\ge1, then βX(v)>0\beta_X(v)>0 for every such vv.

Proof. The blow-up is a plt extraction and the different on GG is zero. The refinement has bounded support, since the order-at-pp filtration of an ample section ring is linearly bounded, and it contains an ample series by the complete jets in Lemma 14.2. Apply [4, Theorem 3.3] to GG and {p}\{p\}. Every centre on GG maps to pp, so the second term in that theorem is precisely δ(G;W)\delta(G;W). This gives (14.1).

Here is also the discrepancy calculation underlying the assertion. For an mm-basis divisor DmD_m compatible with ordG\mathop{\mathrm{ord}}_G, write σ*Dm=Sm(G)G+Γm,Sm(G)=∑jjdimWm,jmNm.\sigma^*D_m=S_m(G)G+\Gamma_m,\qquad S_m(G)=\frac{\sum_j j\dim W_{m,j}}{mN_m}. Then GG is not a component of Γm\Gamma_m, and Γm|G\Gamma_m|_G is a basis divisor of WW. The coefficient of GG in the boundary of the pullback of (X,cDm)(X,cD_m) is cSm(G)−2cS_m(G)-2. It is at most one when cSm(G)≤3cS_m(G)\le3. Inversion of adjunction therefore gives the stated minimum, after passage to the limit. Using a basis compatible with both ordG\mathop{\mathrm{ord}}_G and vv retains the additional discrepancy term. This is [4, equation (3.6)]; since 𝔪p𝒪Y=𝒪Y(−G)\mathfrak m_p\mathcal O_Y=\mathcal O_Y(-G), it gives (14.2). If the two hypotheses in the last assertion hold, use the same inequality with λ=1\lambda=1. For a valuation centred at pp, v(𝔪p)>0v(\mathfrak m_p)>0, proving strict positivity. ◻

The last assertion concerns valuations whose centre equals pp. It does not, by itself, prove δp(X)>1\delta_p(X)>1, since the definition of δp\delta_p also includes positive-dimensional centres containing pp.

Lemma 14.2 (The initial nef interval and the complete jets). The line bundle LL is very ample. For every point pp, Wm,j=H0(ℙ2,𝒪(j))(0≤j≤m),vol(σ*L−tG)=16−t3(0≤t≤1).W_{m,j}=H^0(\mathbb P^2,\mathcal O(j))\quad(0\le j\le m),\qquad \mathop{\mathrm{vol}}(\sigma^*L-tG)=16-t^3\quad(0\le t\le1). If pp lies on a curve Λ≅ℙ1\Lambda\cong\mathbb P^1 with L⋅Λ=1L\cdot\Lambda=1, the nef threshold is exactly one. If q=[TpΛ]∈Gq=[T_p\Lambda]\in G, then (14.3)Wm,j⊂H0(G,𝒪G(j)⊗ℐq)(j>m).\label{f29:eq:line-jets} W_{m,j}\subset H^0(G,\mathcal O_G(j)\otimes\mathcal I_q)\quad(j>m). Such a line passes through every point of the set TT in Proposition 10.2.

Proof. By Lemma 10.5, the morphism (π,φ)(\pi,\varphi) is a closed embedding in ℙ3×ℙ2\mathbb P^3\times\mathbb P^2. Hence L=H+BL=H+B is the restriction of the very ample bundle 𝒪(1,1)\mathcal O(1,1). Choose a section nonzero at pp and three sections vanishing at pp whose linear terms are independent. Their degree-mm products realize every homogeneous polynomial of degree j≤mj\le m as a leading term. This proves the equality of jet spaces.

Hyperplanes through a point of an embedded variety generate its maximal ideal, so σ*L−G\sigma^*L-G is globally generated. Thus σ*L−tG\sigma^*L-tG is nef for 0≤t≤10\le t\le1. Its cube is 16−t316-t^3, giving its volume. On the strict transform of Λ\Lambda it has degree 1−t1-t, proving the threshold assertion. For j>mj>m, a section in ℱjRm\mathcal F^jR_m restricts to zero on Λ\Lambda: a nonzero section of 𝒪ℙ1(m)\mathcal O_{\mathbb P^1}(m) cannot vanish to order greater than mm. Its degree-jj leading term therefore vanishes at qq, proving (14.3).

Every fibre of E→CE\to C has HH-degree zero and BB-degree one. The reduced support of a double conic fibre has HH-degree one and BB-degree zero. These give the required lines through points of TT. ◻

Thus the part of the volume integral with 0≤t≤10\le t\le1 is 63/6463/64. This is only part of SX(G)S_X(G); it must not be used as its full value. Likewise, completeness of the first jets does not justify completeness of the higher jets.

Lemma 14.3 (Bounding point multiplicities by a smooth flag). Let p∈Z⊂S⊂Xp\in Z\subset S\subset X be a flag of subvarieties smooth at pp, of codimensions 3,2,13,2,1. Write Rm=H0(X,−mKX)R_m=H^0(X,-mK_X) and Nm=dimRmN_m=\dim R_m. Choose regular formal parameters x,y,zx,y,z at pp such that S=(x=0)S=(x=0) and Z=(x=y=0)Z=(x=y=0) locally, and trivialize −KX-K_X there. For a nonzero section s∈Rms\in R_m, define ν(s)=(i,j,k)\nu(s)=(i,j,k) by first taking its order ii along SS, then the order jj along ZZ of (s/xi)|S(s/x^i)|_S, and finally the order kk at pp of the remaining nonzero restriction to ZZ after division by yjy^j.

Choose a basis sm,1,…,sm,Nms_{m,1},\ldots,s_{m,N_m} compatible with these lexicographically ordered values, and write ν(sm,r)=(im,r,jm,r,km,r)\nu(s_{m,r})=(i_{m,r},j_{m,r},k_{m,r}). Suppose that the following limits exist: a=limm∑rim,rmNm,b=limm∑rjm,rmNm,c=limm∑rkm,rmNm.a=\lim_m\frac{\sum_r i_{m,r}}{mN_m},\qquad b=\lim_m\frac{\sum_r j_{m,r}}{mN_m},\qquad c=\lim_m\frac{\sum_r k_{m,r}}{mN_m}. They do not depend on the compatible basis: the number of its vectors with any prescribed value is the dimension of the corresponding graded quotient. If GG is the exceptional divisor of BlpX\operatorname{Bl}_pX, then SX(G)≤a+b+cS_X(G)\le a+b+c. For the flags of Section 12, the limits are respectively SX(S),𝒮Z,𝒯pS_X(S),\mathcal S_Z,\mathcal T_p, and hence SX(G)≤SX(S)+𝒮Z+𝒯p.S_X(G)\le S_X(S)+\mathcal S_Z+\mathcal T_p.

Proof. If ν(s)=(i,j,k)\nu(s)=(i,j,k), the formal expansion of ss has a nonzero xiyjzkx^iy^jz^k coefficient. Its multiplicity at pp is therefore at most i+j+ki+j+k. The two-filtration lemma [4, Lemma 3.1] supplies a basis of RmR_m compatible both with multiplicity at pp and with the flag values. Indeed, the finitely many flag values occurring in RmR_m, ordered lexicographically, define a finite filtration by subspaces. The mean multiplicity of this basis, divided by mm, is Sm(G)S_m(G). Summing the preceding inequality over the basis gives Sm(G)≤1mNm∑r=1Nm(im,r+jm,r+km,r).S_m(G)\le\frac1{mN_m}\sum_{r=1}^{N_m} (i_{m,r}+j_{m,r}+k_{m,r}). Passing to the limits proves the inequality. In the flags of Section 12, the surface and curve refinements give the three limits from their definitions and the integrals of Lemma 12.1. ◻

Proposition 14.4 (An explicit estimate for the point extraction). If p∈f0p\in f_0 lies on a smooth conic fibre, then (14.4)SX(G)≤273128,βX(G)≥111128,δp(X)≥min{12891,δ(G;W)}.\label{f29:eq:f0-point-bound} S_X(G)\le\frac{273}{128},\qquad \beta_X(G)\ge\frac{111}{128},\qquad \delta_p(X)\ge\min\left\{\frac{128}{91},\delta(G;W)\right\}. In addition, the cubic-surface flag can be chosen to give δp(X)≥64/65\delta_p(X)\ge64/65. Thus one may take the maximum of this numerical bound and the last bound in (14.4). For comparison, if the conic fibre through pp is reduced and singular, then SX(G)≤221/96S_X(G)\le221/96. If it is smooth and p∉f0p\notin f_0, then SX(G)≤793/384S_X(G)\le793/384.

Proof. First suppose p∈f0p\in f_0 and put Z=φ−1(φ(p))Z=\varphi^{-1}(\varphi(p)). Choose a smooth cubic SaS_a containing ZZ, as in Lemma 10.6. Under the identification Sa≅Sa,0⊂ℙ3S_a\cong S_{a,0}\subset\mathbb P^3, the point pp is p0p_0. The line ℓa\ell_a has direction aa at p0p_0, and aa varies on the parameter line of cubics containing ZZ. The image of ZZ is a fixed smooth plane conic through p0p_0. At most one direction aa is its tangent direction at p0p_0. Avoid it, as well as the finitely many singular cubics. This makes (ℓa⋅Z)p=1(\ell_a\cdot Z)_p=1. Put CSa=E|SaC_{S_a}=E|_{S_a} and μ=(CSa⋅Z)p\mu=(C_{S_a}\cdot Z)_p; since CSa⋅Z=6C_{S_a}\cdot Z=6, we have μ≤6\mu\le6.

Lemmas 14.3 and 12.3 now give SX(G)≤91192+247384+189+μ192=807+2μ384≤819384=273128.S_X(G)\le\frac{91}{192}+\frac{247}{384} +\frac{189+\mu}{192} =\frac{807+2\mu}{384} \le\frac{819}{384}=\frac{273}{128}. Subtracting from AX(G)=3A_X(G)=3 proves the beta bound, and (14.1) gives the last inequality in (14.4).

For this same choice of cubic surface, Lemma 12.1 gives δp(X)≥192189+μ≥192195=6465.\delta_p(X)\ge\frac{192}{189+\mu}\ge\frac{192}{195}=\frac{64}{65}. In particular, if μ≤2\mu\le2, this flag already proves δp(X)>1\delta_p(X)>1.

For a reduced singular fibre, use a line component and Lemma 12.6. The sum is at most (91+161+190)/192=221/96(91+161+190)/192=221/96. For a smooth fibre outside f0f_0, choose ℓ\ell avoiding pp. The sum is at most 91/192+247/384+182/192=793/38491/192+247/384+182/192=793/384. ◻

These are upper bounds for SX(G)S_X(G), not asserted exact values. Their proof uses no Zariski decomposition on YY. The surface calculations already made supply an upper bound for ordinary point multiplicity, and Abban–Zhuang refinement then passes to the actual jet series on GG.

Remark 14.5 (Computing the remaining series without a threefold decomposition). There is a concrete algebraic description of every required jet space. The incidence model of Lemma 10.5 is a complete intersection of bidegrees (1,1)(1,1) and (2,1)(2,1). Its Koszul resolution gives Rm=(ℂ[x0,x1,x2,x3,y0,y1,y2]/(∑liyi,∑qiyi))(m,m),Nm=83m3+4m2+103m+1.R_m=\left(\mathbb C[x_0,x_1,x_2,x_3,y_0,y_1,y_2] \big/\bigl(\textstyle\sum l_iy_i,\sum q_iy_i\bigr)\right)_{(m,m)}, \qquad N_m=\frac83m^3+4m^2+\frac{10}3m+1. Surjectivity onto H0(X,mL)H^0(X,mL) follows from the same resolution and the vanishing of the relevant intermediate cohomology of line bundles on ℙ3×ℙ2\mathbb P^3\times\mathbb P^2.

On an affine chart at pp, solve the two equations formally for two of the five affine coordinates, using the rank-two Jacobian. The other three are regular parameters. Evaluation of the representatives of RmR_m in these parameters gives the jet map Jm,j:Rm→𝒪X,p/𝔪pj.J_{m,j}:R_m\longrightarrow\mathcal O_{X,p}/\mathfrak m_p^j. Writing rm,j=rankJm,jr_{m,j}=\operatorname{rank}J_{m,j}, we obtain the exact formulas dimWm,j=rm,j+1−rm,j,Sm(G)=1mNm∑j≥1(Nm−rm,j).\dim W_{m,j}=r_{m,j+1}-r_{m,j},\qquad S_m(G)=\frac1{mN_m}\sum_{j\ge1}(N_m-r_{m,j}). The degree-jj terms of elements of kerJm,j\ker J_{m,j} also give the actual homogeneous polynomials spanning Wm,jW_{m,j}. Thus jet computations can replace a threefold Zariski decomposition. However, finitely many computed degrees do not establish the necessary asymptotic description, and the ranks alone do not determine δ(G;W)\delta(G;W): the base ideals and their infinitely near behaviour matter.

Example 14.6 (The normalization on projective space). For X=ℙ3X=\mathbb P^3 and L=−KX=𝒪(4)L=-K_X=\mathcal O(4), the same construction gives Wm,j=H0(ℙ2,𝒪(j))W_{m,j}=H^0(\mathbb P^2,\mathcal O(j)) for 0≤j≤4m0\le j\le4m. Here SX(G)=164∫04(64−t3)dt=3.S_X(G)=\frac1{64}\int_0^4(64-t^3)\,dt=3. The weighted average degree of this complete series on GG is three. Since δ(ℙ2;𝒪(1))=3\delta(\mathbb P^2;\mathcal O(1))=3, its threshold is δ(G;W)=1\delta(G;W)=1. The point extraction therefore gives δp(ℙ3)=1\delta_p(\mathbb P^3)=1, the reverse inequality being supplied by GG. In Family 2.9, the base condition (14.3) prevents this completeness argument at the points of TT.

To complete this alternative point-extraction proof at the points in (14.4), one must still prove δ(G;W)>1\delta(G;W)>1, or prove δ(G;W)≥1\delta(G;W)\ge1 and separately treat positive-dimensional centres. The surface blow-up proof in Proposition 12.4 already gives the required local bound on XX. For nonreduced conic fibres, Section 18 instead uses a weighted curve extraction. These assertions do not follow from the calculations of this section alone. Sections 15 and 16 improve the point-extraction term by genuine threefold decompositions, and Section 17 proves δ(G;W)>1\delta(G;W)>1 in the smooth-fibre case. Positivity of βX(G)\beta_X(G) alone would not imply positivity for every divisor lying above pp.