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Section 89

Geometry and the scope of the result

Family 3.5: K-semistability and the complete smooth classification

We prove that every smooth member of Family 3.5 is K-semistable and classify the K-stable and K-polystable members. The mixed fibre requires two additional point extractions. Their actual refined series are identified from sections and exact Hilbert counts; explicit resolutions of conic and cubic pencils then control every divisor over the exceptional surfaces. A weighted extraction of the joining line gives an independent semistability estimate.

Put M=ℙ1×ℙ2M=\mathbb P^1\times\mathbb P^2. Let Q⊂ℙ2Q\subset\mathbb P^2 be a smooth conic, and identify S=ℙ1×QS=\mathbb P^1\times Q with ℙ1×ℙ1\mathbb P^1\times\mathbb P^1 by ([u:v],[x:y])↦([u:v],[y2:xy:x2]).([u:v],[x:y])\longmapsto([u:v],[y^2:xy:x^2]). Choose relatively prime binary quintics f,gf,g. The curve C={uf(x,y)+vg(x,y)=0}⊂SC=\{u f(x,y)+v g(x,y)=0\}\subset S is the graph of a degree-five morphism η:C≅ℙ1→ℙ1\eta:C\cong\mathbb P^1\longrightarrow\mathbb P^1. Thus CC is smooth even when η\eta has high ramification. Conversely, every smooth member of Family 3.5 is obtained as π:X=BlC(M)→M\pi:X=\operatorname{Bl}_C(M)\longrightarrow M in this way; see [3, Sections 5.14 and 7.5]. The bidegree (5,2)(5,2) of CC in MM means that the degrees of the two pulled-back hyperplane bundles on CC are five and two.

Write T=π*𝒪M(1,0)T=\pi^*\mathcal O_M(1,0), H=π*𝒪M(0,1)H=\pi^*\mathcal O_M(0,1), let EE be the exceptional divisor, and let DD be the strict transform of SS. We use TT also for a fibre of ϕ:X→ℙ1\phi:X\to\mathbb P^1. Then D=2H−E,L=−KX=2T+3H−E,L3=20.D=2H-E,\qquad L=-K_X=2T+3H-E,\qquad L^3=20. On D≅ℙ1×ℙ1D\cong\mathbb P^1\times\mathbb P^1, let ℓ1,ℓ2\ell_1,\ell_2 denote the pullbacks of points of its first and second factors. Notice the factor two in the restriction of HH: T|D=ℓ1,H|D=2ℓ2,E|D=ℓ1+5ℓ2,D|D=−ℓ1−ℓ2,L|D=ℓ1+ℓ2.T|_D=\ell_1,\quad H|_D=2\ell_2,\quad E|_D=\ell_1+5\ell_2,\quad D|_D=-\ell_1-\ell_2,\quad L|_D=\ell_1+\ell_2. The intersection identities on XX are TH2=1,TE2=−5,HE2=−2,E3=−14;TH^2=1,\quad TE^2=-5,\quad HE^2=-2,\quad E^3=-14; products with one EE and two pullbacks vanish, as do T2T^2 and H3H^3. Indeed, degNC/M=(−KM)⋅C−2=14\deg N_{C/M}=(-K_M)\cdot C-2=14. These identities give L3=54−48+14=20L^3=54-48+14=20.

Definition 89.1. The ramification index of η\eta at q∈Cq\in C is the integer rr for which, in local coordinates, η\eta has the form t=cxr+O(xr+1)t=c x^r+O(x^{r+1}), with c≠0c\ne0. A ramification point is simple if r=2r=2, and is totally ramified if r=5r=5. The ramification divisor is R=∑q(rq−1)qR=\sum_q(r_q-1)q; the Riemann–Hurwitz formula gives degR=8\deg R=8.

Theorem 89.2 (The smooth Family 3.5 classification). Let XX be a smooth member of Family 3.5. Then XX is K-semistable. More precisely,

  1. If η\eta has no totally ramified point, then δ(X)≥100/99\delta(X)\ge100/99 and XX is K-stable.

  2. If η\eta has a totally ramified point, then XX is K-semistable. If it has two such points, then XX is the K-polystable member corresponding to ux5+vy5=0u x^5+v y^5=0. If it has exactly one, then XX is strictly K-semistable.

The first assertion extends Denisova’s simple-ramification theorem [14]; its proof is completed in Theorem 101.1. The second is [3, Corollary 5.71 and Lemma 7.6]; we give the degeneration and the requisite Abban–Zhuang argument below. The local estimates at index-three and index-four points are respectively δp(X)≥160/151\delta_p(X)\ge160/151 and δp(X)=400/389\delta_p(X)=400/389. For the mixed fibre, the index-two endpoint and the interior of its joining line satisfy δp(X)≥240/221\delta_p(X)\ge240/221 and δp(X)≥32/29\delta_p(X)\ge32/29, respectively. The announced work [15] is not used as an unpublished theorem.